document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111387>Question 111387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve system by substitution,\r<BR>\n" );
document.write( "\n" );
document.write( "x+2y=6<BR>\n" );
document.write( "3x-y=-10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81236 by </B><A HREF=/tutors/aboutme.mpl?userid=BrittanyM><B>BrittanyM(80)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BrittanyM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We must solve for a single variable out of either of the equations first.\r<BR>\n" );
document.write( "\n" );
document.write( "Let's choose x+2y=6<BR>\n" );
document.write( "By isolating the x, we have x=-2y+6\r<BR>\n" );
document.write( "\n" );
document.write( "Now let's plug this into the second equation.<BR>\n" );
document.write( "3(-2y+6)-y=10 <BR>\n" );
document.write( "Using the distributive proporty:<BR>\n" );
document.write( "-6y+18-y=10<BR>\n" );
document.write( "Combine like terms:<BR>\n" );
document.write( "-7y=-8<BR>\n" );
document.write( "y=8/7\r<BR>\n" );
document.write( "\n" );
document.write( "Now plug y into either equation and solve for x.\r<BR>\n" );
document.write( "\n" );
document.write( "x+2(8/7)=6<BR>\n" );
document.write( "x+16/7=6  Let 6 be 42/7<BR>\n" );
document.write( "x=42/7-16/7<BR>\n" );
document.write( "x=26/7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );