document.write( "Question 1182358: How many ounces of a 40% alcohol solution must be mixed with 12 ounces of a 45% alcohol solution to make a 43% alcohol​ solution? \n" ); document.write( "
Algebra.Com's Answer #812351 by Boreal(15235)\"\" \"About 
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x oz.*0.40 alcohol=0.40x oz pure alcohol
\n" ); document.write( "12 oz*0.45 alcohol=5.4 oz pure alcohol
\n" ); document.write( "(12+x) oz of 0.43 alcohol final solution is 5.16 +0.43x oz.
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\n" ); document.write( "Therefore, 0.40x+5.4=5.16+0.43x
\n" ); document.write( "0.03x=0.24
\n" ); document.write( "x=8 oz of 40% (3.2 oz pure)
\n" ); document.write( "12 oz of 45% (5.4 oz pure)
\n" ); document.write( "=20 oz 43% (8.6 oz pure)
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