document.write( "Question 1182358: How many ounces of a 40% alcohol solution must be mixed with 12 ounces of a 45% alcohol solution to make a 43% alcohol​ solution? \n" ); document.write( "
Algebra.Com's Answer #812351 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x oz.*0.40 alcohol=0.40x oz pure alcohol \n" ); document.write( "12 oz*0.45 alcohol=5.4 oz pure alcohol \n" ); document.write( "(12+x) oz of 0.43 alcohol final solution is 5.16 +0.43x oz. \n" ); document.write( "- \n" ); document.write( "Therefore, 0.40x+5.4=5.16+0.43x \n" ); document.write( "0.03x=0.24 \n" ); document.write( "x=8 oz of 40% (3.2 oz pure) \n" ); document.write( "12 oz of 45% (5.4 oz pure) \n" ); document.write( "=20 oz 43% (8.6 oz pure) \n" ); document.write( " |