document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182284>Question 1182284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Recorded here are the germination times (in days) for ten randomly chosen seeds of a new type of bean.<BR>\n" );
document.write( "13, 11, 13, 10, 14, 14, 20, 13, 22, 20<BR>\n" );
document.write( "Assuming that germination times are normally distributed, find a 95% confidence interval for the mean germination time for all beans of this type. Then find the lower limit and upper limit of the 95% confidence interval.<BR>\n" );
document.write( "Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.)\r<BR>\n" );
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document.write( "Lower limit:	<BR>\n" );
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document.write( "Upper limit:	<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812340 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Get the mean and sd<BR>\n" );
document.write( "the 95% CI is mean +/- t (0.975, df=9)*s/sqrt(10)<BR>\n" );
document.write( "the mean is 15, s=4.14<BR>\n" );
document.write( "t=2.262<BR>\n" );
document.write( "the half-interval is 2.262*4.14/sqrt(10)=2.96<BR>\n" );
document.write( "the whole interval is (12.0, 18.0) units days rounded. </SPAN>\n" );
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