document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182020>Question 1182020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a point B is 8km from point A on a bearing of 140 degrees from A. Point C is 9km from A on a bearing of 200 degrees from A. How far is B from C? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812337 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw this triangle with AB=8 an AC=9.<BR>\n" );
document.write( "Angle A is 60 degrees, because the angle from AB to the South line is 40 degrees and there is 20 more degrees to reach AC.<BR>\n" );
document.write( "Use the law of cosines.  <BR>\n" );
document.write( "side a^2 opposite to angle A=b^2+c^2-2bc CosA<BR>\n" );
document.write( "=64+81-2(72)*0.5<BR>\n" );
document.write( "=145-72<BR>\n" );
document.write( "=73 km^2<BR>\n" );
document.write( "a=8.544 km, and this is the distance between B and C. </SPAN>\n" );
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