document.write( "Question 111378: The altitude of a triangle is 3 inches more than its base. What are the dimensions if the area of the triangle is 29 square inches? \n" ); document.write( "
Algebra.Com's Answer #81232 by edjones(8007)![]() ![]() You can put this solution on YOUR website! a=b+3 \n" ); document.write( "ab/2=A \n" ); document.write( "b(b+3)/2=29 \n" ); document.write( "2b(b+3)/2=29*2 \n" ); document.write( "b(b+3)=58 \n" ); document.write( "b^2+3b=58 \n" ); document.write( "b^2+3b-58=58-58 \n" ); document.write( "b^2+3b-58=0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "b=6.262... \n" ); document.write( "a=9.262... \n" ); document.write( "Check: \n" ); document.write( "6.262*9.262/2=29 approx.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |