document.write( "Question 111378: The altitude of a triangle is 3 inches more than its base. What are the dimensions if the area of the triangle is 29 square inches? \n" ); document.write( "
Algebra.Com's Answer #81232 by edjones(8007)\"\" \"About 
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a=b+3
\n" ); document.write( "ab/2=A
\n" ); document.write( "b(b+3)/2=29
\n" ); document.write( "2b(b+3)/2=29*2
\n" ); document.write( "b(b+3)=58
\n" ); document.write( "b^2+3b=58
\n" ); document.write( "b^2+3b-58=58-58
\n" ); document.write( "b^2+3b-58=0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B3x%2B-58+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%283%29%5E2-4%2A1%2A-58=241\".
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\n" ); document.write( " Discriminant d=241 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-3%2B-sqrt%28+241+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%283%29%2Bsqrt%28+241+%29%29%2F2%5C1+=+6.26208734813001\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%283%29-sqrt%28+241+%29%29%2F2%5C1+=+-9.26208734813001\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B3x%2B-58\" can be factored:
\n" ); document.write( " \"1x%5E2%2B3x%2B-58+=+%28x-6.26208734813001%29%2A%28x--9.26208734813001%29\"
\n" ); document.write( " Again, the answer is: 6.26208734813001, -9.26208734813001.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B3%2Ax%2B-58+%29\"

\n" ); document.write( "\n" ); document.write( "b=6.262...
\n" ); document.write( "a=9.262...
\n" ); document.write( "Check:
\n" ); document.write( "6.262*9.262/2=29 approx.\r
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