document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182220>Question 1182220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of the shaded region represents one-third of the total, What is the<BR>\n" );
document.write( "size of the radii such that this is possible? \r<BR>\n" );
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document.write( "The radius of the whole circle is 12cm while the shaded region is a ring in<BR>\n" );
document.write( "the middle with a small not shaded circle in the middle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812301 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The area of the ring is 1/3 the area of the circle with radius 12cm, so the area of the inner circle is 2/3 the area of the large circle.<br><BR>\n" );
document.write( "Since the ratio of the areas of the two circles is 2:3, the ratio of the radii of the two circles is the square root of that ratio -- sqrt(2):sqrt(3).<br><BR>\n" );
document.write( "ANSWER: The radius of the inner circle is<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2A%28sqrt%282%29%2Fsqrt%283%29%29 ALIGN=MIDDLE  ALT=\"12%2A%28sqrt%282%29%2Fsqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 9.7979..., or 9.78 to 2 decimal places.<br><BR>\n" );
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