document.write( "Question 1182202: Determine the number of three figures numbers between 100 and 999 inclusive, have only two consecutive figures identical. (I don't really understand this question.) \n" ); document.write( "
Algebra.Com's Answer #812294 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Perhaps part of your problem in understanding the problem is that the vocabulary and grammar are both poor.... \n" ); document.write( "Determine the number of \n" ); document.write( "Note also that \"between 100 and 999 inclusive\" is redundant, since it repeats the requirement that we are looking at only 3-digit numbers. \n" ); document.write( "There are two kinds of 3-digit numbers that have only two consecutive digits the same: AAB and ABB. \n" ); document.write( "(1) AAB (first two digits the same) \n" ); document.write( "The first digit can be any of 9 digits (it can't be 0): 9 choices \n" ); document.write( "The second digit has to be the same as the first: 1 choice \n" ); document.write( "The third digit has to be different from the first two; and it can be 0: 9 choices \n" ); document.write( "Number of 2-digit numbers of the form AAB: 9*1*9 = 81 (multiply the numbers of choices for each digit) \n" ); document.write( "(2) ABB (last two digits the same) \n" ); document.write( "The first digit can be any of 9 digits (it can't be 0): 9 choices \n" ); document.write( "The second digit has to be different from the first; and it can be 0: 9 choices \n" ); document.write( "The third digit has to be the same as the second: 1 choice \n" ); document.write( "Number of 2-digit numbers of the form AAB: 9*9*1 = 81 \n" ); document.write( "ANSWER: The number of 3-digit numbers with only two consecutive digits the same is \n" ); document.write( "--------------------------------------------- \n" ); document.write( "Thanks to tutor @ikleyn for catching the typo in my answer. \n" ); document.write( " \n" ); document.write( " |