document.write( "Question 1182280: A committee of 5 people is going to be chosen from a group of 8 women and 10
\n" );
document.write( "men. How many different committees are possible if the committee must
\n" );
document.write( "contain at least 1 woman and at least 1 man?\r
\n" );
document.write( "\n" );
document.write( "How many committees are possible if the committee must have 3 women and 2 men?\r
\n" );
document.write( "\n" );
document.write( "How many committees are possible if the committee must have more women than men? \n" );
document.write( "
Algebra.Com's Answer #812255 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! A committee of 5 people is going to be chosen from a group of 8 women and 10 \n" ); document.write( "men. There are 18 people choose 5 committee members. that's 18C5 = 8568 ways to\r\n" ); document.write( "select a committee of 5 people.How many different committees are possible if the committee must contain at \n" ); document.write( "least 1 woman and at least 1 man? From the 8568 ways to choose 5 people, we must eliminate and subtract those\r\n" ); document.write( "which \r\n" ); document.write( "\r\n" ); document.write( "1. contain only women. That's 8 women choose 5 or 8C5=56 \r\n" ); document.write( "2. contain only men. That's 10 men choose 5 or 10C5=252 \r\n" ); document.write( "\r\n" ); document.write( "That's 56+252=308 that we must subtract from the 8568.\r\n" ); document.write( "\r\n" ); document.write( "Answer = 8568-308 = 8260.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |