document.write( "Question 1182257: A standardized​ exam's scores are normally distributed. In a recent​ year, the mean test score was 1462 and the standard deviation was 319. The test scores of four students selected at random are 1890​,1180 ​,2210,and 1350. Find the​ z-scores that correspond to each value and determine whether any of the values are unusual.\r
\n" ); document.write( "\n" ); document.write( "The​ z-score for 1890 is____? \r
\n" ); document.write( "\n" ); document.write( "Round to two decimal places as​ needed.)
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Algebra.Com's Answer #812250 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "mu = population mean = 1462
\n" ); document.write( "sigma = population standard deviation = 319\r
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\n" ); document.write( "\n" ); document.write( "z = (x - mu)/sigma
\n" ); document.write( "z = (1890-1462)/319
\n" ); document.write( "z = 1.34 approximately\r
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\n" ); document.write( "\n" ); document.write( "I would consider this to be not unusual. In other words, it seems fairly likely. Any z score such that \"-2+%3C=+z+%3C=+2\" would be considered usual; anything outside this interval is considered unusual. Keep in mind that your teacher may use another interval, so I would check with them about that. Though usually, if a z score is further than 2 standard deviations from the mean, then it's considered unusual.
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