document.write( "Question 1182238: A man adds 1.6 liters of a 60% antifreeze solution to the water already in his car radiator. When the radiator is filled the solution is 8% antifreeze. How many liters does the radiator hold? (Hint: The water is a 0% antifreeze solution) \n" ); document.write( "
Algebra.Com's Answer #812205 by mananth(16946) You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Antifreeze 60 ---------------- 1.6 l \n" ); document.write( "water 0 ---------------- x l \n" ); document.write( "Mixture 8 ---------------- 1.6 + x l \n" ); document.write( " \n" ); document.write( " 0.6 * 1.6 + 0 x = 0.08 ( 1.6 + x) \n" ); document.write( " \n" ); document.write( " 0.96 + 0 x= 0.128 + 0.08 x) \n" ); document.write( " \n" ); document.write( " -0.08 x= 0.128 - 0.96 \n" ); document.write( " -0.08 x= -0.832 - \n" ); document.write( " x= 10.4 liters of water was there in the radiator\r \n" ); document.write( "\n" ); document.write( "10.4+1.6 = 12 liters holding capacity \n" ); document.write( " \n" ); document.write( " |