document.write( "Question 1182238: A man adds 1.6 liters of a 60% antifreeze solution to the water already in his car radiator. When the radiator is filled the solution is 8% antifreeze. How many liters does the radiator hold? (Hint: The water is a 0% antifreeze solution) \n" ); document.write( "
Algebra.Com's Answer #812205 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Antifreeze 60 ---------------- 1.6 l
\n" ); document.write( "water 0 ---------------- x l
\n" ); document.write( "Mixture 8 ---------------- 1.6 + x l
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\n" ); document.write( " 0.6 * 1.6 + 0 x = 0.08 ( 1.6 + x)
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\n" ); document.write( " 0.96 + 0 x= 0.128 + 0.08 x)
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\n" ); document.write( " -0.08 x= 0.128 - 0.96
\n" ); document.write( " -0.08 x= -0.832 -
\n" ); document.write( " x= 10.4 liters of water was there in the radiator\r
\n" ); document.write( "\n" ); document.write( "10.4+1.6 = 12 liters holding capacity
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