document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111307>Question 111307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would appreciate your help in solving this nonlinear equation:<BR>\n" );
document.write( "Problem: (x+2)^2+(y-2)^2=13 (1)<BR>\n" );
document.write( "         (        2x+y=6    (2)\r<BR>\n" );
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document.write( "Thank you greatly for all your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81220 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the second equation to find y (y=6-2x) and then substitute this value into the first equation\r<BR>\n" );
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document.write( "(x+2)^2+(6-2x-2)^2=13 ___ x^2+4x+4+16-16x+4x^2=13 ___ 5x^2-12x+7=0 ___ (5x-7)(x-1)=0\r<BR>\n" );
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document.write( "plug the x values back into the second equation to find the corresponding y values ___ there will be two pairs\r<BR>\n" );
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document.write( "this is a line intersecting a circle (at two points) </SPAN>\n" );
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