document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182168>Question 1182168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ryan has a bag of marbles with 4 blue marbles, 3 white marbles, and 6 red marbles.<BR>\n" );
document.write( "Find the following probabilities of Ryan drawing the given marbles from the bag if the first marble(s) is (are) not returned to the bag after they are drawn.<BR>\n" );
document.write( "(Answer as a reduced fraction)<BR>\n" );
document.write( "a  A Blue, then a Red = ________<BR>\n" );
document.write( "b  A Red, then a White = _______<BR>\n" );
document.write( "c  A Blue, then a Blue, then a Blue = _______ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812159 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total number of marbles: 4+3+6 = 13<br>\r<BR>\n" );
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document.write( "a) There are 4 outcomes (of 13 possible) for choosing blue:  4/13 for choosing blue.<BR>\n" );
document.write( "That leaves 12 marbles in the bag, of which 6 are red, so 6/12 for choosing red on the 2nd choice.<br><BR>\n" );
document.write( "  <BR>\n" );
document.write( "P(blue then red) = (4/13)*(6/12) = 2/13 <br>\r<BR>\n" );
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document.write( "Parts (b) and (c) are solved in a similar manner.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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