document.write( "Question 1182156: Hi
\n" ); document.write( "Originally the ratio of the width of a rectangle to the length is 4 to 3. The rectangle is altered such that its width and length each increase by 5 inches. The area of the new rectangle is greater than the area of the old rectangle by 200 square inches. What are the length and width of the original rectangle.
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Algebra.Com's Answer #812136 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Original length and width, 4x and 3x\r
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\n" ); document.write( "\n" ); document.write( "New dimensions, 4x+5 and 3x+5
\n" ); document.write( "Increased area, 200 sq. in.s\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%2B5%29%283x%2B5%29-4x%2A3x=200\"
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\n" ); document.write( "\"12x%5E2%2B15x%2B20x%2B25-12x%5E2=200\"
\n" ); document.write( "\"35x=200-25\"
\n" ); document.write( "\"35x=175\"
\n" ); document.write( "\"highlight%28x=5%29\"\r
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\n" ); document.write( "\n" ); document.write( "original dimensions, 20 and 15
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