document.write( "Question 1182131: I saw this solution online from a tutor (ikelyn). I think there's a mistake in it and i need to make sure I'm right. So in case b in this solution. Shouldn't the equation be 8*8*7*4 = 1792? (4 because there are 4 different possible digits?) In the solution it says 8*8*7 = 448. \r
\n" ); document.write( "\n" ); document.write( "The solution:\r
\n" ); document.write( "\n" ); document.write( "How many 4-digit even numbers can be formed from the digits 0 to 9
\n" ); document.write( "if each digit is to be used only once in each number ?\r
\n" ); document.write( "\n" ); document.write( "Solution\r
\n" ); document.write( "\n" ); document.write( "The fact that the number is an EVEN number means that the last digit is one of 5 even digits 0, 2, 4, 6, or 8.\r
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\n" ); document.write( "\n" ); document.write( "In my solution, I will consider two cases separately:\r
\n" ); document.write( "\n" ); document.write( " case (a): the last digit is 0 (zero),\r
\n" ); document.write( "\n" ); document.write( " and\r
\n" ); document.write( "\n" ); document.write( " case (b): the last digit is any of the remaining 4 even digits 2, 4, 6 or 8.\r
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\n" ); document.write( "\n" ); document.write( "Case (a): the last digit is 0 (zero)\r
\n" ); document.write( "\n" ); document.write( " Then the first (most-left) digit is any of 9 remaining digits;\r
\n" ); document.write( "\n" ); document.write( " the second digit is any of remaining 8 digits;\r
\n" ); document.write( "\n" ); document.write( " the third digit is any of remaining 7 digits.\r
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\n" ); document.write( "\n" ); document.write( " So, the total number of possible options is 9*8*7 = 504 in this case.\r
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\n" ); document.write( "\n" ); document.write( "Case (b): the last digit is any of remaining 4 digits 2, 4, 6 or 8.\r
\n" ); document.write( "\n" ); document.write( " Then the first (most-left) digit is any of 8 remaining digits (keep in mind that the leading digit CAN NOT be 0 (!));\r
\n" ); document.write( "\n" ); document.write( " the second digit is any of 8 remaining digits (zero is ALLOWED in this position);\r
\n" ); document.write( "\n" ); document.write( " the third digit is any of 7 remaining digits (zero is ALLOWED in this position).\r
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\n" ); document.write( "\n" ); document.write( " So, the total number of possible options is 8*8*7 = 448 in this case.\r
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\n" ); document.write( "\n" ); document.write( "Thus the total number of possibilities is 504 + 448 = 952.\r
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\n" ); document.write( "\n" ); document.write( "ANSWER. 952 four-digit even numbers can be formed from the digits 0 to 9 if each digit is to be used only once in each number.
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Algebra.Com's Answer #812100 by math_tutor2020(3816)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Yes you are correct. \r
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\n" ); document.write( "\n" ); document.write( "There are 8 choices for slot one, 8 for slot two, 7 for slot three, and 4 choices for the last slot.\r
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\n" ); document.write( "\n" ); document.write( "So the final answer would be 504+1792 = 2296
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