document.write( "Question 1182100:
\n" );
document.write( "Angela’s average for six math tests is 87. On her first four tests she had scores of 93, 87, 82, and 86. On her last test, she scored 4 points lower than she did on her fifth test. What scores did Angela receive on her fifth and sixth tests?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #812064 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "In problems involving averages of numbers that are close together, I find it faster and easier to solve the problem using an \"over/under\" strategy, rather than the formal definition of an average. \n" ); document.write( "In this problem, using this strategy makes solving the problem almost trivial, because the average on her first four tests is 87. This is easily seen by looking at the \"overs\" and \"unders\" for those tests: \n" ); document.write( "93: +6 \n" ); document.write( "87: +0 \n" ); document.write( "82: -5 \n" ); document.write( "86: -1 \n" ); document.write( "total overs and unders on tests 1 to 4: 0 \n" ); document.write( "That means the average of her fifth and sixth tests must also be 87. And since her score on her sixth test was 4 points lower than on her fifth, simple logical reasoning tells us her scores on her fifth and sixth tests were 87+2=89 and 87-2=85. \n" ); document.write( "ANSWERS: \n" ); document.write( "5th test 89 \n" ); document.write( "6th test 85 \n" ); document.write( " \n" ); document.write( " |