document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182096>Question 1182096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 3.0kg cinder block is dragged down a (horizontal)pinic table. If the coefficient of kinetic friction is 0.8 what is the friction force on the block </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #812054 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52788)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=812054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "The friction force is the product of the weight  &nbsp;&nbsp;3.0 kg * 10 m/s^2 = 30 &nbsp;Newtons  by the kinetic friction coefficient of &nbsp;0.8.\r<BR>\n" );
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document.write( "So, &nbsp;your answer is  &nbsp;&nbsp;30*0.8 = 24 N.\r<BR>\n" );
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