document.write( "Question 111370: Given 3 sides of a rectangular fence have a perimeter of 80 feet. Find the largest possible area. \n" ); document.write( "
Algebra.Com's Answer #81201 by jim_thompson5910(35256)\"\" \"About 
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The formula for the perimeter of rectangle is \"P=2L%2B2W\", but since we have 3 sides, the formula becomes \"P=L%2B2W\"\r
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\n" ); document.write( "\n" ); document.write( "Now set the perimeter P equal to 80\r
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\n" ); document.write( "\n" ); document.write( "\"80=L%2B2W\"\r
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\n" ); document.write( "\n" ); document.write( "Now solve for L\r
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\n" ); document.write( "\n" ); document.write( "\"L=80-2W\"\r
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\n" ); document.write( "\n" ); document.write( "Now the area of a rectangle is \"A=L%2AW\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=%2880-2W%29%2AW\" Plug in \"L=80-2W\"\r
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\n" ); document.write( "\n" ); document.write( "Now plot \"A=%2880-2W%29%2AW\" as a function of x. Simply change A to y and w to x to get \"y=%2880-2x%29%2Ax\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-50%2C+50%2C+-10%2C+800%2C+%2880-2x%29%2Ax%29+\"\r
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\n" ); document.write( "\n" ); document.write( "From the graph we can see that the max is at x=20, which means y=800. So when the width is 20 ft the area is maxed out at 800 square feet
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