document.write( "Question 1182028: In ∆ACS, AC = 12, SA = 8 and SC = 16. Determine the measures of all the interior angles of the triangle. \n" ); document.write( "
Algebra.Com's Answer #811986 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "In ∆ACS, AC = 12, SA = 8 and SC = 16. Determine the measures of all the interior angles of the triangle.
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document.write( "Use the cosine law\r\n" );
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document.write( "    c^2 = a^2 + b^2 - 2bccos(C),\r\n" );
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document.write( "where \"a\", \"b\", \"c\" are the lengths of the three sides of a triangle, and C is the angle opposite to the side \"c\".\r\n" );
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document.write( "It gives\r\n" );
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document.write( "    cos(C) = \"%28a%5E2%2Bb%5E2-c%5E2%29%2F%282bc%29\".\r\n" );
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document.write( "Apply this formula to each angle of the triangle\r\n" );
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document.write( "    angle A, a= 12, b= 8, c= 16;  cos(A) = \"%2812%5E2+%2B+8%5E2+-+16%5E2%29%2F%282%2A12%2A8%29\" = -0.25;\r\n" );
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document.write( "                                  A = arccos(0.25) = 1.823 radians = 104.48 degrees.\r\n" );
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document.write( "    angle C, a= 12, b= 16, c= 8;  cos(A) = \"%2812%5E2+%2B+16%5E2+-+8%5E2%29%2F%282%2A12%2A16%29\" = 0.875;\r\n" );
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document.write( "                                  C = arccos(0.875) = 0.505 radians = 28.96 degrees.\r\n" );
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document.write( "    angle S, a= 8, b= 16, c= 12;  cos(S) = \"%2816%5E2+%2B+8%5E2+-+12%5E2%29%2F%282%2A16%2A8%29\" = 0.6875;\r\n" );
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document.write( "                                  C = arccos(68.75) = 0.813 radians = 46.57 degrees.\r\n" );
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document.write( "The problem is just solved: all the angles are found.\r\n" );
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document.write( "As a conclusion, I will check the sum of angles  104.48 + 28.96 + 46.57 = 180 degrees,   ! correct !\r\n" );
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