document.write( "Question 1182008: The length of a rectangle is 5m less than twice the width, and the area of the rectangle is \"52m%5E2\" . Find the dimensions of the rectangle.\r
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Algebra.Com's Answer #811971 by ikleyn(52804)\"\" \"About 
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document.write( "Let w be the width, in meters;\r\n" );
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document.write( "then the length is (2w-5) meters, according to the condition.\r\n" );
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document.write( "Write the area equation\r\n" );
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document.write( "    w*(2w-5) = 52 m^2.\r\n" );
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document.write( "From the equation,\r\n" );
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document.write( "    2w^2 - 5w - 52 = 0.\r\n" );
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document.write( "Use the quadratic formula\r\n" );
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document.write( "    \"w%5B1%2C2%5D\" = \"%285+%2B-+sqrt%285%5E2+-+4%2A2%2A%28-52%29%29%29%2F%282%2A2%29\" = \"%285+%2B-+sqrt%28441%29%29%2F4\" = \"%285+%2B-+21%29%2F4\".\r\n" );
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document.write( "You need the positive root  w = \"%285+%2B+21%29%2F4\" = 6.5 m.     \r\n" );
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document.write( "ANSWER.  The width is 6.5 meters;  the length is  2*6.5 - 5 = 8 meters.\r\n" );
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document.write( "CHECK.   6.5*8 = 52 m^2.    ! Correct !\r\n" );
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