document.write( "Question 1181953: Alice stopped by a coffee shop two days in a row at a conference to buy drinks and
\n" ); document.write( "pastries. On the first day, she bought a cup of coffee and two muffins for which she
\n" ); document.write( "paid |6.87. The next day she bought two cups of coffee and three muffins (for herself
\n" ); document.write( "and a friend). Her bill was |11.25. Use the method of elimination to determine the
\n" ); document.write( "price of a cup of coffee, and the price of a muffin. Clearly explain your set-up for the
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Algebra.Com's Answer #811912 by mananth(16946)\"\" \"About 
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$ x Price of one coffee
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\n" ); document.write( "1 x + 2.00 y = 6.87
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\n" ); document.write( "2 x + 3.00 y = 11.25 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -3
\n" ); document.write( "Multiply (2) by 2
\n" ); document.write( "-3 x -6 y = -20.61
\n" ); document.write( "4 x 6 y = 22.50
\n" ); document.write( "Add the two equations
\n" ); document.write( "1.00 x = 1.89
\n" ); document.write( "/ 1.00
\n" ); document.write( "x = 1.89
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1.00 x + 2.00 y = 6.87
\n" ); document.write( "1.89 + 2.00 y = 6.87
\n" ); document.write( " 2.00 y = 4.98
\n" ); document.write( " y = 2.49
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\n" ); document.write( "$ 1.89 Price of one coffee
\n" ); document.write( "$ 2.49 Price of one muffin
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