document.write( "Question 1181909: What is the factored form equation for a parabola that has x-intercepts at -3 and 1 and vertex point at (- 1, -8). \n" ); document.write( "
Algebra.Com's Answer #811861 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "If p and q are roots of a quadratic, then x-p and x-q are the two factors.\r
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\n" ); document.write( "\n" ); document.write( "Based on that, we have the roots -3 and 1 lead us to the factors (x+3) and (x-1)\r
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\n" ); document.write( "\n" ); document.write( "Notice that the expression (x+3)(x-1), when set equal to zero, will result in x = -3 or x = 1 as the two roots. I'm using the zero product property.\r
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\n" ); document.write( "\n" ); document.write( "In other words, solving (x+3)(x-1) = 0 will get us x = -3 and x = 1 as the two roots.\r
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\n" ); document.write( "\n" ); document.write( "That takes care of the x intercept portion. Now let's consider the vertex point. \r
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\n" ); document.write( "\n" ); document.write( "Let's see if plugging x = -1 leads to y = -8
\n" ); document.write( "(x+3)(x-1) = (-1+3)(-1-1) = (2)(-2) = -4
\n" ); document.write( "Unfortunately, we don't reach the target we want.
\n" ); document.write( "We can fix this by sticking a 2 out front, so that we scale the -4 up to -8\r
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\n" ); document.write( "\n" ); document.write( "Trying x = -1 again gets us
\n" ); document.write( "2(x+3)(x-1) = 2(-1+3)(-1-1) = 2(2)(-2) = -8
\n" ); document.write( "and now everything works out\r
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\n" ); document.write( "\n" ); document.write( "Answer: 2(x+3)(x-1)\r
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\n" ); document.write( "\n" ); document.write( "Graph:
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\n" ); document.write( "Points A and B are the roots, aka x intercepts.
\n" ); document.write( "Point C is the vertex.
\n" ); document.write( "Because the vertex is below the x axis, and there are two x intercepts, this must mean the parabola opens upward (hence the positive leading coefficient a = 2)
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