document.write( "Question 1181905: A sticker warehouse sells an average of 6 rolls of stickers per customer at $4 per roll. Statistics show that for every $0.25 decrease in price, customers will buy an additional roll. According to this model, at what sticker price will the revenue from stickers be $28. \n" ); document.write( "
Algebra.Com's Answer #811856 by Theo(13342)![]() ![]() You can put this solution on YOUR website! price * number of items = revenue. \n" ); document.write( "when the price is 4.00, the average number of rolls per customer is 6. \n" ); document.write( "with every .25 decrease in price, the average number rolls per customer goes up 1. \n" ); document.write( "the euation is y = (4 - .25x) * (6 + x). \n" ); document.write( "when x = 0, the equation becomes y = 4 * 6 = 24 \n" ); document.write( "when x = 1, the equation becomes y = 3.75 * 7 = 23.25 \n" ); document.write( "when x = 2, the equation becomes y = 3.5 * 8 = 28\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the revenue will be 28 when the sticker price is 3.5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a graph of the equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph shows that, when x = 2. \n" ); document.write( "this gets a price per ticket of 3.5 with an average number of 8 tickets per customer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the maximum revenue occurs when x = 5. \n" ); document.write( "this gets a price per ticket of 2.75 with an average number of 11 tickets per customer. \n" ); document.write( " |