document.write( "Question 1181573: The heights of 200 plants in a garden follow a normal distribution with a mean of 72.3 cm with a standard
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document.write( "deviation of 8.9 cm.
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document.write( "a. about how many plants whose heights are between 82 and 90 cm?
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document.write( "b. about how many plants whose heights are between 70 and 75 cm?
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document.write( "c. if 20% of the tallest plants are to be trimmed, then what is the starting height of the plants that the
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document.write( "gardener must choose to trim? \n" );
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Algebra.Com's Answer #811819 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "a. z=9.7/8.9 and 17.7/8.9 or 1.09 and 1.99. That probability is 0.1146 \n" ); document.write( "b. z=-2.3/8.9 and 2.7/8.9 or -0.26 and 0.30 with probability of 0.2204 \n" ); document.write( "check with 2nd VARS2normalcddf(82,90,72.3,8.9) which is more accurate because the z-values above were rounded, But it is only to the fourth decimal place in the first and 0.0008 different in the second. Ask how accurate it should be. \n" ); document.write( "c.80th percentile has a z of 0.8416. (can use 3invnorm(0.80,0,1) to get the z-value \n" ); document.write( "so 0.846=(x-72.3)/8.9 \n" ); document.write( "7.49=x-72.3 \n" ); document.write( "x=79.8 cm \n" ); document.write( " |