document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181859>Question 1181859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> State the sidelength of AC and AB. Please view link for diagram.\r<BR>\n" );
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document.write( "https://docs.google.com/document/d/1Cl3HrcoR6jibNzxfDTIilS3imSplLY8nQUU0OpU9vLA/edit?usp=sharing </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811790 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The given information makes it possible to use the law of cosines to find the length of AC.  But I think I would go a different route.<br><BR>\n" );
document.write( "In triangle ACD, draw altitude DE to side AC.  Since the triangle is isosceles, that makes DEC and DEA congruent right triangles.  Then use<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%2835%29=CE%2F10 ALIGN=MIDDLE  ALT=\"sin%2835%29=CE%2F10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "to find CE and double that to find AC.<br><BR>\n" );
document.write( "Then, knowing AC, use<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%2832%29=AB%2FAC ALIGN=MIDDLE  ALT=\"tan%2832%29=AB%2FAC\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "to find AB.<br><BR>\n" );
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