document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181839>Question 1181839</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which polynomial is prime?\r<BR>\n" );
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document.write( "3x3 + 3x2  -  2x  -  2 <BR>\n" );
document.write( "3x3  -  2x2 + 3x  -  4 <BR>\n" );
document.write( "4x3 + 2x2 + 6x + 3 <BR>\n" );
document.write( "4x3 + 4x2  -  3x  -  3 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811768 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811768\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "None of those are prime.  Three of them can be easily factored by grouping.<br><BR>\n" );
document.write( "3x^3 + 3x^2 - 2x - 2 = (3x^2)(x+1)-2(x+1) : (x+1) is a factor<br><BR>\n" );
document.write( "3x^3 - 2x^2 + 3x - 4 : x=1 makes the expression equal to 0, so (x-1) is a factor<br><BR>\n" );
document.write( "4x^3 + 2x^2 + 6x + 3 = (2x^2)(2x+1)+3(2x+1) : (2x+1) is a factor<br><BR>\n" );
document.write( "4x^3 + 4x^2 - 3x - 3 =4x^2(x+1)-3(x+1) : (x+1) is a factor<br><BR>\n" );
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