document.write( "Question 1181777: Prove that the sum of three exterior angles of a triangle fromed by producing the sides in order is four right angles or 360° \n" ); document.write( "
Algebra.Com's Answer #811720 by ikleyn(52776)\"\" \"About 
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document.write( "Let  \"alpha\", \"beta\"  and  \"gamma\" are three interior angles of the triangle.\r\n" );
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document.write( "Then the respective exterior angles are  \"180%5Eo+-+alpha\",  \"180%5Eo+-+beta\"  and  \"180%5Eo+-+gamma\".\r\n" );
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document.write( "The sum of exterior angles is then\r\n" );
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document.write( "    \"180%5Eo+-+alpha\" + \"180%5Eo+-+beta\" + \"180%5Eo+-+gamma\" = \"540%5Eo+-++%28alpha%2Bbeta%2Bgamma%29\" = 540° - 180° = 360°,\r\n" );
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document.write( "since the sum of interior angles of any triangle is 180°.\r\n" );
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