document.write( "Question 111316: Find two consecutive integers such that the sum of 3 times the first integer and 7 times second integer is 97. \n" ); document.write( "

Algebra.Com's Answer #81172 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let first consecutive integer be $\"x\"$ , and let second consecutive integer be $\"y+=+x%2B1\"$ \r
\n" ); document.write( "\n" ); document.write( "Then:
\n" ); document.write( " $\"3x+%2B+7y+=+97\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"3x+%2B+7%28x%2B1%29+=+97\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x+%2B+7x+%2B+7+=+97\"$ Е.move $\"7\"$ to the right\r
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\n" ); document.write( "\n" ); document.write( " $\"+10x++=+97+-+7\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+10x++=+90\"$ ЕЕЕ..divide both sides by $\"10\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+10x%2F10++=+90%2F10\"$ ЕЕЕ..\r
\n" ); document.write( "\n" ); document.write( " $\"+x++=+9\"$ ЕЕЕ..first consecutive integer\r
\n" ); document.write( "\n" ); document.write( "Now find second consecutive integer\r
\n" ); document.write( "\n" ); document.write( " $\"y+=+x%2B1+=+9+%2B+1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y+=+10\"$ ЕЕЕЕЕЕ.. second consecutive integer\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( " $\"3x+%2B+7y+=+97\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3%2A9+%2B+7%2810%29+=+97\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"27+%2B+70+=+97\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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