document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181767>Question 1181767</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the S12 for tn= 2(3) ^(n-1)<BR>\n" );
document.write( "S12 means Sum of 12<BR>\n" );
document.write( "I attempted this several times and I got, 1062882, another time I got 531440.\r<BR>\n" );
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document.write( "I appreciate any help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811659 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "S12 = 2(3)^0+2(3)^1+2(3)^2+...+2(3)^(n-1)<br><BR>\n" );
document.write( "S12 = 2((3)^0+(3)^1+(3)^2+...+(3)^(n-1))<br><BR>\n" );
document.write( "Apply the formula for the sum of a finite geometric series:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S12+=+2%28%281-3%5E12%29%2F%281-3%29%29+=+3%5E12-1+=+531440 ALIGN=MIDDLE  ALT=\"S12+=+2%28%281-3%5E12%29%2F%281-3%29%29+=+3%5E12-1+=+531440\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The second answer you show is correct.<br><BR>\n" );
document.write( "Your first answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%283%5E12%29 ALIGN=MIDDLE  ALT=\"2%283%5E12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "It is possible that for that answer you were using the correct formula but did the calculation incorrectly....<br><BR>\n" );
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