document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181743>Question 1181743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In order to double the capacity of a spherical balloon, by what percentage must the area of the material on its surface be increased? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811631 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume of a sphere = V = 4/3pi*R^3<BR>\n" );
document.write( "V1 = 4/3pi*R1^3<BR>\n" );
document.write( "V2 = 4/3pi*R2^3<BR>\n" );
document.write( "If the volume is doubled, V2 = 2V1 -> 4/3pi*R2^3 = 8/3pi*R1^3<BR>\n" );
document.write( "Thus, R2 = (2)^(1/3)*R1<BR>\n" );
document.write( "Since the surface area of a sphere = S = 4pi*R^2, S2/S1 = R2^2/R1^2 = <BR>\n" );
document.write( "((2)^(1/3)*R1)^2/R1^2 = (4)^(1/3) = 1.587<BR>\n" );
document.write( "Thus the surface area must increase by 58.7%<BR>\n" );
document.write( " </SPAN>\n" );
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