document.write( "Question 1181643: four grapefruit (considered spheres) 6 in. in diameter are placed in a square box whose inside base dimensions are 12 in. in the space between the first 4 grapefruit a fifth of the same diameter is placed. how deep must the box be so that the top will just touch the fifth grapefruit. \n" ); document.write( "
Algebra.Com's Answer #811607 by ikleyn(52786)\"\" \"About 
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\n" ); document.write( "four grapefruit (considered spheres) 6 in. in diameter are placed in a square box
\n" ); document.write( "whose inside base dimensions are 12 in. in the space between the first 4 grapefruit
\n" ); document.write( "a fifth of the same diameter is placed. how deep must the box be so that the top
\n" ); document.write( "will just touch the fifth grapefruit.
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document.write( "(a)  The centers of the first 4 spheres are vertices of a square with the side length of 2*3 = 6 inches.\r\n" );
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document.write( "(b)  The diagonal of this square is  \"6%2Asqrt%282%29\" inches long.\r\n" );
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document.write( "     The half of this diagonal is  \"3%2Asqrt%282%29\"  inches long .\r\n" );
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document.write( "(c)  Now consider the right angled triangle formed by the centers of the 1st and 5th spheres as the hypotenuse,\r\n" );
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document.write( "     vertical line from the center of the 5th spere as the leg, \r\n" );
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document.write( "     and the horizontal line from the center of the 1st sphere coinciding with the diagonal of the above mentioned square.\r\n" );
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document.write( "(d)  The hypotenuse of this triangle is 2 times the radius of 3 cm, i.e. 6 inches.\r\n" );
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document.write( "     Its leg, parallel to the diagonal of the square, is  \"3%2Asqrt%282%29\"  inches long.\r\n" );
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document.write( "     Having it, you just can calculate the length of the vertical leg. It is\r\n" );
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document.write( "          \"sqrt%286%5E2+-+%283%2Asqrt%282%29%29%5E2%29\" = \"sqrt%2836+-+9%2A2%29\" = \"sqrt%2818%29\" = \"3%2Asqrt%282%29\".\r\n" );
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document.write( "          ( It is interesting to note, that it MEANS that the line connecting centers of the 1st and the 5th square\r\n" );
document.write( "            is inlined 45 degrees to horizon (!) )\r\n" );
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document.write( "(e)  Thus we found that the center of the 5th sphere is elevated  \"3%2Asqrt%282%29\"  inches over the plane of the centers \r\n" );
document.write( "     of the first four spheres.\r\n" );
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document.write( "(f)  Combining the gained information, we see that the depth of the box must be equal to \r\n" );
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document.write( "               \"3+%2B+3%2Asqrt%282%29+%2B+3\" = \"6+%2B+3%2Asqrt%282%29\" inches = 10.243 inches (rounded).\r\n" );
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document.write( "ANSWER.  The depth of the box should be equal to  \"6+%2B+3%2Asqrt%282%29\" inches = 10.243 inches  (rounded).\r\n" );
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