document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181640>Question 1181640</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The distance between two towns A and B, is 90 km. John cycles from A to B whereas Harry<BR>\n" );
document.write( " cycles from B to A. They start cycling towards each other at the same time.John cycles twice<BR>\n" );
document.write( " as fast as Harry does. If they meet 2 hours later, at what average speed is each cyclist traveling? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811547 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let h = Harry's speed, and j = John's speed<BR>\n" );
document.write( "Then their relative speed, traveling toward each other is h + j<BR>\n" );
document.write( "Since they travel 90 km in 2 h, we can equate their relative speed to 90/2 [km/h]<BR>\n" );
document.write( "Since, j = 2h, we have<BR>\n" );
document.write( "3h = 45 -> h = 15 km/h<BR>\n" );
document.write( "Thus Harry's speed is 15 km/h and John's is 30 km/h </SPAN>\n" );
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