document.write( "Question 1181585: When tickets at a dance cost $4, the expected attendance is 300 people. for every $0.10 increase in ticket price, the dance committee projects that the attendance will decrease by 5 people. what would be the maximum revenue? what ticket price would maximize the revenue? \n" ); document.write( "
Algebra.Com's Answer #811493 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Ticket price as is = $4\r\n" ); document.write( "Attendence with ticket price as is = 300\r\n" ); document.write( "Revenue with ticket price as is = (300)($4) = $1200\r\n" ); document.write( "\r\n" ); document.write( "Let x = the number of ten-cent increases made in the ticket price.\r\n" ); document.write( "Then the ticket price will increase by $0.10x, making the \r\n" ); document.write( "new higher ticket price be $4+$0.10x.\r\n" ); document.write( "\r\n" ); document.write( "That will also cause the attendance to decrease by 5x.\r\n" ); document.write( "Then the new lower attendance will be 300-5x.\r\n" ); document.write( "\r\n" ); document.write( "Let y = the new higher (hopefully) revenue (the amount of money taken in\r\n" ); document.write( "from selling all the tickets at the new higher ticket price and the new\r\n" ); document.write( "lower attendance).\r\n" ); document.write( "\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |