document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181531>Question 1181531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please view the document for the two questions.\r<BR>\n" );
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document.write( "https://docs.google.com/document/d/1Cl3HrcoR6jibNzxfDTIilS3imSplLY8nQUU0OpU9vLA/edit?usp=sharing </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811469 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a1= 120 first<BR>\n" );
document.write( "common ratio = 1/5 ( ratio of consecutive terms)<BR>\n" );
document.write( "last term = 24/78125\r<BR>\n" );
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document.write( "an = a1*r^(n-1)\r<BR>\n" );
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document.write( "24/78125 = 120*(1/5)^(n-1)\r<BR>\n" );
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document.write( "(1/5)^(n-1) = 1/390625\r<BR>\n" );
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document.write( "(n-1) log (1/5) = log(1/390625)\r<BR>\n" );
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document.write( "n-1=8<BR>\n" );
document.write( "n=9 the number of terms\r<BR>\n" );
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document.write( "2-(4/3) +(8/9)-(16/27) ....\r<BR>\n" );
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document.write( "=> (2+(8/9) .....) - ((4/3) +16/27) ....)\r<BR>\n" );
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document.write( "Use the sum of n terms formula for both and simplify\r<BR>\n" );
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document.write( " </SPAN>\n" );
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