document.write( "Question 1181538: Three cards are pulled from a deck of 52 cards. The probability of obtaining atleast one club is? \n" ); document.write( "
Algebra.Com's Answer #811441 by Theo(13342)\"\" \"About 
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the probability of obtaining at least one club is 1 minus the probability of obtaining zero clubs.
\n" ); document.write( "there are 13 clubs in the deck.
\n" ); document.write( "that leaves 52 minus 13 = 39 cards in the deck that are not clubs.
\n" ); document.write( "if you assume no replacement, then the probability changes each time.
\n" ); document.write( "on the first draw, the probability of not drawing a club is 39/52.
\n" ); document.write( "on the second draw, the probability of not drawing a club is 38/51.
\n" ); document.write( "third draw = 37/50.
\n" ); document.write( "fourth draw = 36/49.
\n" ); document.write( "fifth draw = 35/48.
\n" ); document.write( "sixth draw = 34/47.
\n" ); document.write( "seventh draw = 33/46.
\n" ); document.write( "eighth draw = 32/45.
\n" ); document.write( "ninth draw = 31/44.
\n" ); document.write( "tenth draw = 30/43.
\n" ); document.write( "eleventh draw = 29/42.
\n" ); document.write( "twelth draw = 28/41.
\n" ); document.write( "thirteenth draw = 27/40
\n" ); document.write( "the probability of getting zero clubs is therefore equal to:
\n" ); document.write( "39/52 * 38/51 * 37/50 * 36/49 * 35/48 * 34/47 * 33/46 * 32/45 * 31/44 * 30/43 * 29/42 * 28/41 * 27/40 which is equal to:
\n" ); document.write( "(39*38*37*36*35*34*33*32*31*30*29*28*27) / (52*51*50*49*48*47*46*45*44*43*42*41*40)
\n" ); document.write( "which is equal to:
\n" ); document.write( ".012790948
\n" ); document.write( "the probability of getting at least one club is therefore 1 minus that which is equal to: .987209052.\r
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