document.write( "Question 1181523: A shipment of assembly parts from a vendor offering inexpensive parts is used in a manufacturing plant. The box of 12 parts contains 5 that are defective and will not fit during assembly. A worker picks parts one at a time and attempts to install them. Find the probability of each outcome.\r
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Algebra.Com's Answer #811430 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "A shipment of assembly parts from a vendor offering inexpensive parts is used in a manufacturing plant.
\n" ); document.write( "The box of 12 parts contains 5 that are defective and will not fit during assembly.
\n" ); document.write( "A worker picks parts one at a time and attempts to install them. Find the probability of each outcome.
\n" ); document.write( "(a) The first two chosen are both good.
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\n" ); document.write( "(c) The first four picked are all good.
\n" ); document.write( "(d) The worker has to pick five parts to find one that is good.
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\n" ); document.write( "\n" ); document.write( "At the beginning, there are 7 good and 5 defective parts in the set of 12 parts.\r
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document.write( "(a)  P = \"%287%2F12%29%2A%286%2F11%29\" = reduce fractions = \"%287%2F2%29%2A%281%2F11%29\" = \"7%2F22\".    ANSWER\r\n" );
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document.write( "         Quite simple:  \"7%2F12\"  is the probability to get first good part from the set of 12 parts;\r\n" );
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document.write( "                        \"6%2F11\"  is the probability to get the second good part from remaining 6 good \r\n" );
document.write( "                              parts among remaining 11 parts.\r\n" );
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document.write( "(b)  P =  = \"%287%2A5+%2B+28%2A5+%2B+35%2A1%29%2F220\" = \"210%2F220\" =  is the total number of different selection 3 parts of 12 parts.\r\n" );
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document.write( "         The numerator is the number of favorable sets of 3 parts, containing at least 1 good part of the 3.\r\n" );
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document.write( "(c)  P = \"%287%2F12%29%2A%286%2F11%29%2A%285%2F10%29%2A%284%2F9%29\" = reduce fractions = \"%287%2F2%29%2A%281%2F11%29%2A%281%2F2%29%2A%284%2F9%29\" = \"7%2A%281%2F11%29%2A%281%2F9%29\" = \"7%2F99\".    ANSWER\r\n" );
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document.write( "         The same logic works as in part (a).\r\n" );
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\n" ); document.write( "\n" ); document.write( "Let me stop at this point: I do not like to answer tooooooooo many questions at a a time.\r
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