document.write( "Question 1181509: A pipe 3.0m long was cut into three pieces. The first piece and the second one were measured as 1.3m and 0.94m respectively. Find the limits within which the length of the third piece lies. \n" ); document.write( "

Algebra.Com's Answer #811428 by Solver92311(821) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Since the length of piece 1 measured 1.3 meters, we know that the true measure of that length,

is in the range

. Similarly,

. So the greatest that that sum of the measures of the two pieces could be would be

meters and the shortest the sum could be is

. However, the original piece of pipe could be actually in the range

. So the shortest the third length could be is the smallest the original pipe could be minus the longest the sum of the first two pieces could be, namely

meters and the longest the third piece could be is the longest the original pipe could be minus the shortest the sum of the first two pieces could be, namely

meters.\r
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\n" ); document.write( "\n" ); document.write( "Therefore:\r
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\n" ); document.write( "\n" ); document.write( "From
\n" ); document.write( "I > Ø
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