document.write( "Question 1181517: In a collection of coins there are twice as many nickels as dimes and 7 less quarters than dimes. Find the
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document.write( "number of each coin if the collection is worth $16.25. \n" );
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Algebra.Com's Answer #811421 by mananth(16946)![]() ![]() You can put this solution on YOUR website! In a collection of coins there are twice as many nickels as dimes and 7 less quarters than dimes. \r \n" ); document.write( "\n" ); document.write( "If dimes are x then nickels are 2x\r \n" ); document.write( "\n" ); document.write( "quarters are x-7\r \n" ); document.write( "\n" ); document.write( "Total is $16.25 = 1625 cents\r \n" ); document.write( "\n" ); document.write( "10x + 5(2x) +25(x-7)=1625\r \n" ); document.write( "\n" ); document.write( "20x + 25x - 175 = 1625\r \n" ); document.write( "\n" ); document.write( "45x = 1800 \n" ); document.write( "x = 40 \n" ); document.write( "Dimes - 40 \n" ); document.write( "Nickels = 2x = 80 \n" ); document.write( "quarters x-7 = 33 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |