document.write( "Question 1181514: Find a polynomial function of lowest degree with rational coefficients that has the given numbers as some of its zeros. 5-i, SQUARE ROOT 11 \n" ); document.write( "
Algebra.Com's Answer #811420 by Solver92311(821)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Both complex and irrational zeros come in conjugate pairs. This means that if \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the degree of a polynomial function is equal to the number of zeros, and since you are given one complex zero and one irrational zero there must, at a minimum, be four zeros, you are looking for a fourth-degree polynomial.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We also know that if \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You were given \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Putting it all together, your polynomial function, in factored form, is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only thing left for you to do is to multiply the four binomials and collect like terms. Hints: The product of two conjugates is the difference of two squares and \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( "From \n" ); document.write( "I > Ø \n" ); document.write( " |