document.write( "Question 1181493: Write the standard form equation of the line that is perpendicular to
\n" ); document.write( "6x - 7y - 1 = 0 and passes through (0, -2).
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Algebra.Com's Answer #811392 by greenestamps(13216)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Especially if you are just learning basic algebra, you should understand how to solve the problem as shown by the other tutor:

\n" ); document.write( "determine the slope of the given line;
\n" ); document.write( "determine the slope of the line perpendicular to the given line; and
\n" ); document.write( "find the equation of the line with that slope passing through the given point.

\n" ); document.write( "Here is a more advanced method that is faster and easier.

\n" ); document.write( "Any line parallel to the given line 6x-7y-1=0 will have an equation in standard form of 6x-7y+C=0, where C can be any constant (the coefficients of x and y will be the same as in the given equation).

\n" ); document.write( "Any line perpendicular to the given line 6x-7y-1=0 will have an equation in standard form of 7x+6y+D=0, where again D is some constant. Note to get that form, the coefficients of x and y switch places, and one of them changes sign.

\n" ); document.write( "Use that form and the given point (0,-2) to determine the constant.

\n" ); document.write( "7(x)+6(y)+D=0
\n" ); document.write( "7(0)+6(-2)+D=0
\n" ); document.write( "-12+D=0
\n" ); document.write( "D=12

\n" ); document.write( "ANSWER: 7x+6y+12=0

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