document.write( "Question 1181493: Write the standard form equation of the line that is perpendicular to
\n" ); document.write( "6x - 7y - 1 = 0 and passes through (0, -2).
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Algebra.Com's Answer #811388 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Write the standard form equation of the line that is perpendicular to
\n" ); document.write( "\"6x+-+7y+-+1+=+0\" and passes through (\"0\", \"-2\").\r
\n" ); document.write( "\n" ); document.write( "first write \"6x+-+7y+-+1+=+0\" in slope intercept form\r
\n" ); document.write( "\n" ); document.write( "\"6x-1+=7y+\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%286%2F7%29x-1%2F7+\"=> a slope is \"m=%286%2F7%29\"\r
\n" ); document.write( "\n" ); document.write( "the line that is perpendicular to given line is negative reciprocal to \"m=%286%2F7%29\"\r
\n" ); document.write( "\n" ); document.write( "\"m%5Bp%5D=-1%2F%286%2F7%29\"\r
\n" ); document.write( "\n" ); document.write( "\"m%5Bp%5D=-7%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "use slope point formula to find equation of the line that is perpendicular to given line\r
\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%5Bp%5D%28x-x%5B1%5D%29\"........substitute a slope, and coordinates of given point (\"0\", \"-2\")\r
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\n" ); document.write( "\n" ); document.write( "\"y-%28-2%29=-%287%2F6%29%28x-0%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B2=-%287%2F6%29x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-%287%2F6%29x-2\"-> write it in standard form \"ax%2Bby=c\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-%287%2F6%29x-2\".......both sides multiply by \"6\"\r
\n" ); document.write( "\n" ); document.write( "\"6y=-7x-12\"\r
\n" ); document.write( "\n" ); document.write( "\"7x%2B6y=-12\"\r
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