document.write( "Question 1181430: How many different 4-digit even numbers can be formed from the digits 1,3,5,6,8, and 9 if no repetition of digits is allowed? \n" ); document.write( "

Algebra.Com's Answer #811336 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "How many different 4-digit even numbers can be formed from the digits 1,3,5,6,8, and 9
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document.write( "For the last (ones) digit, you have only two options: you must have it either 6 or 8.\r\n" );
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document.write( "For the 1-st (leftmost) digit, you have any of remaining 5 digits (from original 6 digits);\r\n" );
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document.write( "For the next, 2-nd      digit, you have any of remaining 4 digits;\r\n" );
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document.write( "For the next, 3-rd      digit, you have any of remaining 3 digits.\r\n" );
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document.write( "Thus, in all, you have 2*5*4*3 = 120 options and 120 possible numbers, as described.\r\n" );
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