document.write( "Question 1181243: https://media.discordapp.net/attachments/723023718497910816/849268803228663808/unknown.png?width=447&height=121 \n" ); document.write( "
Algebra.Com's Answer #811298 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Look at the diagram with AC a side of the rhombus and the semicircle with center B on side AC and radius BD.

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\n" ); document.write( "Let r be the radius of the semicircle, BD; BC is also a radius.

\n" ); document.write( "Triangle ABD is a 30-60-90 right triangle in which the radius is the long leg. That makes the length of AB \"%282%2Fsqrt%283%29%29r\".

\n" ); document.write( "But AB+BC=BC=3. So

\n" ); document.write( "\"%28r%29%2B%28%282%2Fsqrt%283%29%29r%29=3\"

\n" ); document.write( "Use a calculator to solve that to find the radius; then use the formula for the area of a semicircle to get the answer to the problem.

\n" ); document.write( "I leave that much of the problem to you.

\n" ); document.write( "Note my result for the area of the semicircle is 3.045 square units, which is actually good to 4 decimal places.

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