document.write( "Question 1181370: 2cos to the power 2 theta =cos theta \n" ); document.write( "
Algebra.Com's Answer #811280 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"2cos%5E2+%28theta%29+=cos%28+theta%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2cos%5E2%28theta%29-cos%28+theta%29+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%282cos%28theta%29-1%29cos%28+theta%29+=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"cos%28+theta%29+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"theta+=cos%5E-1%28+0%29\"\r
\n" ); document.write( "\n" ); document.write( "\"theta+=pi%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2cos%28theta%29-1=0\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28theta%29+=1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"theta=cos%5E-1%281%2F2%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"theta=pi%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "cosine periodicity is \"2pi\"\r
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\n" ); document.write( "\n" ); document.write( " all the solutions:\r
\n" ); document.write( "\n" ); document.write( "\"theta=pi%2F3%2B2pi%2An\"\r
\n" ); document.write( "\n" ); document.write( "\"theta=5p%2F3%2B2pi%2An\"\r
\n" ); document.write( "\n" ); document.write( "\"theta=pi2%2B2pi%2An\"\r
\n" ); document.write( "\n" ); document.write( "\"theta=3pi%2F2%2B2pi%2An\"\r
\n" ); document.write( "\n" ); document.write( "Degrees:\r
\n" ); document.write( "\n" ); document.write( "\"theta=60%2B360\"°*\"n\"
\n" ); document.write( "\"theta=300%2B360\"°*\"n\"
\n" ); document.write( "\"theta=90%2B360\"°*\"n\"
\n" ); document.write( "\"theta=270%2B360\"°*\"n\"\r
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