document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111223>Question 111223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am graphing a parabola and I have all of my points done but I'm having a problem getting the x & y vertex's....the equation is 3x²-x-1=0 ...I have 1.5 for x but I'm told this is wrong and I have no idea how to solve it for the y vertex. Please help!<BR>\n" );
document.write( "            Thanks so much!<BR>\n" );
document.write( "                          B. Cook </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81121 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=3X^2-X-1<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+3x%5E2+-x+-1%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+3x%5E2+-x+-1%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 3x^2 -x -1). <BR>\n" );
document.write( "x=-b/2a<BR>\n" );
document.write( "x=-(-1/2*3)<BR>\n" );
document.write( "x=-(-1/6)<BR>\n" );
document.write( "x=1/6 answer for the x coordinate of the vertex.<BR>\n" );
document.write( "y=3(1/6)^2-1/6-1<BR>\n" );
document.write( "y=3(1/36)-1/6-1<BR>\n" );
document.write( "y=3/36-1/6-1<BR>\n" );
document.write( "y=1/12-1/6-1<BR>\n" );
document.write( "y=(1-2-12)/12<BR>\n" );
document.write( "y=-13/12 the y coordinate of the vertex.<BR>\n" );
document.write( "vertex=(1/6,-13/12) </SPAN>\n" );
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