document.write( "Question 111223: I am graphing a parabola and I have all of my points done but I'm having a problem getting the x & y vertex's....the equation is 3x²-x-1=0 ...I have 1.5 for x but I'm told this is wrong and I have no idea how to solve it for the y vertex. Please help!
\n" ); document.write( " Thanks so much!
\n" ); document.write( " B. Cook
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Algebra.Com's Answer #81120 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
In general, for \"ax%5E2%2Bbx%2Bc\", vertex at (h, k), \"h=-b%2F%282a%29\", and \"k=ah%5E2%2Bbh%2Bc\".
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\n" ); document.write( "So, for your particular problem, b = -1 and a = 3. That makes \"h=%28-%28-1%29%29%2F%282%2A3%29=1%2F6\", and
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\n" ); document.write( "\"k=3%281%2F6%29%5E2-%281%2F6%29-1\"
\n" ); document.write( "\"k=3%2F36-1%2F6-1\"
\n" ); document.write( "\"k=3%2F36-6%2F36-36%2F36\"
\n" ); document.write( "\"k=-39%2F36\"
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\n" ); document.write( "Putting the vertex squarely on the point (1/6,-39/36)
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\n" ); document.write( "Send me a note if there is any part of that you don't understand.
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\n" ); document.write( "John
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