document.write( "Question 1181295: The length of the rectangle is one more than the width. If the dimensions are both decreased by 2 units, the area of the new rectangle is 30 sq. units less than the area of the original rectangle. Find the area of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #811180 by josgarithmetic(39630) ![]() You can put this solution on YOUR website! Original dimensions, w+1 and w.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dimensions of original rectangle, 9 units length, 8 units width \n" ); document.write( " |