document.write( "Question 1181295: The length of the rectangle is one more than the width. If the dimensions are both decreased by 2 units, the area of the new rectangle is 30 sq. units less than the area of the original rectangle. Find the area of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #811180 by josgarithmetic(39630)\"\" \"About 
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Original dimensions, w+1 and w.\r
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\n" ); document.write( "\n" ); document.write( "\"%28w-1%29%28w-2%29=-30%2Bw%28w%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"w%5E2%2Bw-30=w%5E2-3w%2B2\"
\n" ); document.write( "\"w-30=-3w%2B2\"
\n" ); document.write( "\"4w=32\"
\n" ); document.write( "\"w=8\"\r
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\n" ); document.write( "\n" ); document.write( "Dimensions of original rectangle, 9 units length, 8 units width
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