document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181261>Question 1181261</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A long-jumper leaves the ground at an angle of 20º ablve the horizontal at a speed of 11m/s. (a) how far does he jump in the horizontal direction? (b) what is the maximum height reached? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811139 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let v0= the initial speed = 11 m/s<BR>\n" );
document.write( "Then the time to reach maximum height = t = v0sin(20)/g = 0.3835 s<BR>\n" );
document.write( "The total flight time = t_tot = 2*0.3835 = 0.7670 s<BR>\n" );
document.write( "The max. height h = (v0sin(20))^2/(2g) = 0.7214 m<BR>\n" );
document.write( "The range in the horizontal direction = v0cos(20)*t_tot = 11*0.9397*0.767 <BR>\n" );
document.write( "= 7.928 m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );