document.write( "Question 111205This question is from textbook university of Phoenix Elementary and Intermediate Algebra
\n" ); document.write( ": Ok here is my 3rd question for the day.
\n" ); document.write( "Solve the equation:
\n" ); document.write( "x^2-225=0\r
\n" ); document.write( "\n" ); document.write( "do i add 225 to both sides to start out?\r
\n" ); document.write( "\n" ); document.write( "Thanks so much!!
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Algebra.Com's Answer #81110 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2-225=0\"
\n" ); document.write( ":
\n" ); document.write( "Yes, adding 225 to both sides is the correct first step.
\n" ); document.write( ":
\n" ); document.write( "\"x%5E2=225\"
\n" ); document.write( ":
\n" ); document.write( "Then take the square root of both sides, remembering to consider both the positive and negative square roots.
\n" ); document.write( ":
\n" ); document.write( "\"x+=+15\" or \"x+=+-15\"
\n" ); document.write( ":
\n" ); document.write( "There is another way to solve this one, and that is to recognize that you are dealing with the difference of two squares, i.e. \"a%5E2-b%5E2=%28a%2Bb%29%28a-b%29\".
\n" ); document.write( "Hence: \"x%5E2-225=0\"
\n" ); document.write( "\"%28x%2B15%29%28x-15%29=0\"
\n" ); document.write( "Giving you the same result:
\n" ); document.write( "\"x+=+15\" or \"x+=+-15\"
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