document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180933>Question 1180933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5) The number of calls received by a call center follows a Poisson distribution with an average of 5 calls<BR>\n" );
document.write( "per minute. For a 1 minute period,<BR>\n" );
document.write( "a. Find the expected value.<BR>\n" );
document.write( "b. Find the probability of receiving no more than 2 calls. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811091 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean/expected value of the Poisson distribution is the parameter, here 5 calls per minute.<BR>\n" );
document.write( "no more than two calls is p(0,1,2)<BR>\n" );
document.write( "probability of 0 calls is e^-5*5^0/0!=0.0067<BR>\n" );
document.write( "1 call is e^-5*5^1/1!=0.0337<BR>\n" );
document.write( "2 calls is e^-5*5^2/2!=0.0842<BR>\n" );
document.write( "that sum is 0.1246 rounding each step 0.1247 using no rounding until the end (preferred).<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );