document.write( "Question 111199: I keep getting stuck on this problem (below is what I keep getting)
\n" ); document.write( "The problem is....Solve for xby completing the square: x^2+6x=2\r
\n" ); document.write( "\n" ); document.write( "What I can get
\n" ); document.write( "x^2+6x=2
\n" ); document.write( "6x^2=2
\n" ); document.write( "6(x^2)=2\r
\n" ); document.write( "\n" ); document.write( "I cant get any further, can you please tell me what i did wrong. Thank you so much!!!!
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Algebra.Com's Answer #81107 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2B6x=2\"
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\n" ); document.write( "Follow this procedure to solve a quadratic by completing the square:
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\n" ); document.write( "Step 1: Put the equation in the form \"ax%5E2%2Bbx=c\". In this case you don't have to do anything because it is already in the proper form.
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\n" ); document.write( "Step 2: Find divide the coefficient on the 'x' term by 2: 6/2 = 3
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\n" ); document.write( "Step 3: Square this result: 3 * 3 = 9
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\n" ); document.write( "Step 4: Add this result to both sides of the original equation
\n" ); document.write( "\"x%5E2%2B6x%2B9=11\"
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\n" ); document.write( "Step 5: Factor the left side of the equation. This should be easy because you added the 9 to make the left side a perfect square.
\n" ); document.write( "\"%28x%2B3%29%5E2=11\"
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\n" ); document.write( "Step 6: Take the square root of both sides and then add -3 to both sides. Don't forget that you need to consider both the positive and negative square roots.
\n" ); document.write( "\"x=-3%2B-sqrt%2811%29\"
\n" ); document.write( "\"x=-3%2Bsqrt%2811%29\", or
\n" ); document.write( "\"x=-3-sqrt%2811%29\"
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